On 5/22/06 7:19 AM, "Duane L. Mitchell" <[log in to unmask]> wrote:

> set time of d to (0 * hours) + 1

set time of d to 1

'time' part of dates is measured in seconds. A plain old 1 is what you want
with this method.

> 
> As does this:
> 
> tell (current date) to set {day, year, its month, day, time, d} to {1, 2003,
> January, 1, 0 * hours + 1, it}

tell (current date) to set {day, year, its month, day, time, d} to {1, 2003,
January, 1, 1, it}


-- 
Paul Berkowitz