On 5/22/06 7:19 AM, "Duane L. Mitchell" <[log in to unmask]> wrote: > set time of d to (0 * hours) + 1 set time of d to 1 'time' part of dates is measured in seconds. A plain old 1 is what you want with this method. > > As does this: > > tell (current date) to set {day, year, its month, day, time, d} to {1, 2003, > January, 1, 0 * hours + 1, it} tell (current date) to set {day, year, its month, day, time, d} to {1, 2003, January, 1, 1, it} -- Paul Berkowitz