On 5/22/06 7:19 AM, "Duane L. Mitchell" <[log in to unmask]> wrote:
> set time of d to (0 * hours) + 1
set time of d to 1
'time' part of dates is measured in seconds. A plain old 1 is what you want
with this method.
>
> As does this:
>
> tell (current date) to set {day, year, its month, day, time, d} to {1, 2003,
> January, 1, 0 * hours + 1, it}
tell (current date) to set {day, year, its month, day, time, d} to {1, 2003,
January, 1, 1, it}
--
Paul Berkowitz
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